UNIX and Linuxsedelflord@panix.com |
Useful information mostly written by me, the conspicuous exception being the bash manpage ...
Intro to Unix ^ |
matches the beginning of the line |
$ |
matches the end of the line |
. |
Matches any single character |
(character)* |
match arbitrarily many occurences of (character) |
(character)? |
Match 0 or 1 instance of (character) |
[abcdef] |
Match any character enclosed in [] (in this instance, a b c d e or f)
ranges of characters such as [a-z] are permitted. The behaviour
of this deserves more description. See the page on grep
for more details about the syntax of lists.
|
[^abcdef] |
Match any character NOT enclosed in [] (in this instance, any character other than a b c d e or f) |
(character)\{m,n\} |
Match m-n repetitions of (character) |
(character)\{m,\} |
Match m or more repetitions of (character) |
(character)\{,n\} |
Match n or less (possibly 0) repetitions of (character) |
(character)\{n\} |
Match exactly n repetitions of (character) |
\(expression\) |
Group operator. |
\n |
Backreference - matches nth group |
expression1\|expression2 |
Matches expression1 or expression 2. Works with GNU sed, but this feature might not work with other forms of sed. |
/
is a special character
in sed. The reason for this will become very clear when studying
sed commands.
s
sommand. s
means "substitute" or search and replace.
The format is
s/regular-expression/replacement text/{flags}
We won't discuss all the flags yet. The one we use below is g
which means "replace all matches"
>cat file
I have three dogs and two cats
>sed -e 's/dog/cat/g' -e 's/cat/elephant/g' file
I have three elephants and two elephants
>
OK. So what happened ? Firstly, sed read in the line of the file and
executed
s/dog/cat/g
which produced the following text:
I have three cats and two cats
and then the second command was performed on the edited line
and the result was
I have three elephants and two elephants
We actually have a name for the "current text": it is called the
pattern space. So a precise definition of what sed does
is as follows :
sed reads the standard input into the pattern space, performs a sequence of editing commands on the pattern space, then writes the pattern space to STDOUT.
>sed -e 'command1' -e 'command2' -e 'command3' file
>{shell command}|sed -e 'command1' -e 'command2'
>sed -f sedscript.sed file
>{shell command}|sed -f sedscript.sed
so sed can read from a file or STDIN, and the commands can
be specified in a file or on the command line.
Note the following :
that if the commands are read from a file, trailing whitespace can be fatal, in particular, it will cause scripts to fail for no apparent reason. I recommend editing sed scripts with an editor such as vim which can show end of line characters so that you can "see" trailing white space at the end of line.
[address1[ ,address2]]s
/pattern/replacement/[flags]
The flags can be any of the following:
n | replace nth instance of pattern with replacement |
g |
replace all instances of pattern with replacement |
p |
write pattern space to STDOUT if a successful substitution takes place |
w file |
Write the pattern space to file if a successful substitution takes place |
If no flags are specified the first match on the line is replaced.
note that we will almost always use the s
command with
either the g
flag or no flag at all.
If one address is given, then the substitution is applied to lines
containing that address. An address can be either a regular expression
enclosed by forward slashes /regex/
, or
a line number . The $
symbol can be used in place of
a line number to denote the last line.
If two addresses are given separated by a comma, then the substitution is applied to all lines between the two lines that match the pattern.
This requires some clarification in the case where both addresses are patterns, as there is some ambiguity here. more precisely, the substitution is applied to all lines from the first match of address1 to the first match of address2 and all lines from the first match of address1 following the first match of address2 to the next match of address1 Don't worry if this seems very confusing (it is), the examples will clarify this.
[address1[ , address2 ] ]d
And it deletes the content of the pattern space. All following commands are
skipped (after all, there's very little you can do with an empty pattern space),
and a new line is read into the pattern space.
>cat file
http://www.foo.com/mypage.html
>sed -e
's@http://www.foo.com@http://www.bar.net@' file
http://www.bar.net/mypage.html
Note that we used a different delimiter, @ for the substitution
command. Sed permits several delimiters for the s command including
@%,;: these alternative delimiters are good for substitutions which
include strings such as filenames, as it makes your sed code much more
readable.
>cat file
the black cat was chased by the brown dog
>sed -e 's/black/white/g' file
the white cat was chased by the brown dog
That was pretty straight forward. Now we move on to something more interesting.
>cat file
the black cat was chased by the brown dog.
the black cat was not chased by the brown dog
>sed -e '/not/s/black/white/g' file
the black cat was chased by the brown dog.
the white cat was not chased by the brown dog.
In this instance, the substitution is only applied to lines matching
the regular expression not
. Hence it is not applied to the
first line.
>cat file
line 1 (one)
line 2 (two)
line 3 (three)
Example 4a
>sed -e '1,2d' file
line 3 (three)
Example 4b
>sed -e '3d' file
line 1 (one)
line 2 (two)
Example 4c
>sed -e '1,2s/line/LINE/' file
LINE 1 (one)
LINE 2 (two)
line 3 (three)
Example 4d
>sed -e '/^line.*one/s/line/LINE/' -e '/line/d' file
LINE 1 (one)
3a : This was pretty simple: we just deleted lines 1 to 2.^line.*one
So the substitution is carried out, and the resulting pattern space
looks like this:
LINE 1 (one)
So now the second command is executed, but since the pattern space
does not match the regular expression line
, the delete command
is not executed.
>cat file
hello
this text is wiped out
Wiped out
hello (also wiped out)
WiPed out TOO!
goodbye
(1) This text is not deleted
(2) neither is this ... ( goodbye )
(3) neither is this
hello
but this is
and so is this
and unless we find another g**dbye
every line to the end of the file gets deleted
>sed -e '/hello/,/goodbye/d' file
(1) This text is not deleted
(2) neither is this ... ( goodbye )
(3) neither is this
This illustrates how the addressing works when two
pattern addresses are specified. sed finds the first match of the expression
"hello", deleting every line read into the pattern space until it gets
to the first line after the expression "goodbye". It doesn't apply the
delete command to any more addresses until it comes across the expression
"hello" again. Since the expression "goodbye" is not on any subsequent line,
the delete command is applied to all remaining lines.
q
command is very simple. It simply quits. No more
lines are read into the pattern space and the program terminates and produces
no more output.
In sed, curly braces, { } are used to group commands. They are used as follows:
address1[,address2]{
commands }
This example makes very good use of all the concepts outlined above.
For this, we use a shell script, since we need to state the one long string
X
several times (otherwise, we'd need to repeat ourselves three
times with a somewhat lengthy expression). Notice that we use double quotes.
This is so that $X
is expanded to the shell variable name
(which would not happen if we used single quotes). Also notice the $1
on the end. The syntax to run this script is
script search_filename
where script
is whatever you
decided to call it and search_filename
is the file you are trying to
search. $1
is the name the shell gives to the first command line
argument.
#!/bin/sh X='word1\|word2\|word3\|word4\|word5' sed -e " /$X/!d /$X/{ s/\($X\).*/\1/ s/.*\($X\)/\1/ q }" $1An important note: it is tempting to think of this:
s/\($X\).*/\1/
s/.*\($X\)/\1/
as redundant, and to try and shorten it with this:
s/.*\($X\).*/\1/
This is unlikely to work. Why ? suppose we have a line
word1 word2 word3
we have no way of knowing that $X
is going to match word1 , word2
or word3, so when we quote it (\1
) , we don't know what we are
quoting.
What has been used to make sure there are no such problems in the correct implementation is this:
the * operator is greedy. That is, when there is ambiguity as to what (expression)* can match, it tries to match as much as possible.So in the example,
s/\($X\).*/\1/
, .*
tries to swallow as much
of the line as possible. in particular, if the line looks like
word1 word2 word3
then we can be sure that .*
matches " word2 word3"
and hence $X
matches word1
.
s/pattern1/replacement/
does not work if the
string spans more than one line.
Microsoft Windows 95
with Linux
(I mean, just replace the text !). Our first attempt is
this:
s/Microsoft Windows 95/Linux/gUnfortunately, the script fails if our file looks like this:
Microsoft
Windows 95
Since neither line matches the pattern microsoft Windows 95
So we need to do better.
We need the "multiline next" or N
command.
The next command N appends the next line to the pattern space.So our second attempt is this:
N N s/Microsoft[ \t\n]*Windows[ \t\n]*95/Linux/gNow note that we have made reference to
\t
and \n
.
These are the tab and end of line characters respectively. The end of line
character only appears in multiline patterns. In multiline patterns, it should
also be noted that ^
and $
match the beginning and
end of the pattern space.
The above is a start, but it breaks if we have a file that looks like this:
Foo Microsoft Windows 95
Why does it break ? Let's look at what the script does.
Foo\nMicrosoft
Foo\nMicrosoft\nWindows
Foo\nMicrosoft\nWindows
This doesn't match the search pattern, so no substitution is
performed.
This is the main error in the script : once the end of the script is reached, the first line that * has not been read into the pattern space already * is read. It is NOT true that the Nth iteration of the script reads from the Nth line of the file.The following too N commands fail and the script exits without writing '95' to STDOUT.
So there are too things to be learned from this:
A better version is as follows:
/Microsoft[ \t]*$/{ N } /Microsoft[ \t\n]*Windows[ \t]*$/{ N } s/Microsoft[ \t\n]*Windows[ \t\n]*95/Linux/gThis only performs the search on extra lines when necessary.
Suppose we want to eliminate all text enclosed by a matching pair of delimiters This is a problem that comes up frequently. For example, removing html commands from html documents. We will use <angle brackets> in this example. So the task then is to eliminate anything between matching pairs of these brackets.
Our first attempt is shown as follows:
s/<[^>]*>//gBut this might break: the angle brackets might span more than one line, or there may be nested angle brackets. Actually, the latter is unlikely to happen if the html is correct. only possible to nest angle brackets inside html comments. ) But we will assume that it might happen anyway (since it makes the problem more fun) So here is the improved version.
:top /<.*>/{ s/<[^<>]*>//g t top } /</{ N b top }A fine point: why didn't we replace the third line of the script with
s/<[^>]*>//g
and removing the t command that follows ? Well consider this sample file:
<<hello> hello>The desired output would be the empty set, since everything is enclosed in angled brackets. However, the output will look like this:
hello>since the first line matches the expression
<[^>]*>
So the point is that we have set up the script to recursively remove
the contents of the innermost matching pair of delimiters.